Optimization by Pravin Varaiya
Author:Pravin Varaiya
Language: eng
Format: epub
Tags: Optimization,
Figure 5.8: h(x k ) is a feasible direction.
Call h(x) an optimum solution of (5.46) and let ho(x) = ip(x)(h(x)) be the minimum value attained. (Note that by Exercise 1 of 4.5.1 (5.46) can be solved as an LP.)
The following algorithm is due to Topkis and Veinott [1967]. Step 1. Find x° G $7, set k = 0, and go to Step 2.
Step 2. Solve (5.46) for x = x k and obtain ho(x k ), h(x k ). If ho(x k ) = 0, stop, otherwise go to Step 3.
Step 3. Compute an optimum solution fi(x k ) to the one-dimensional problem,
Maximize fo(x k + /j,h(x k )) ,
subject to (x k + fih(x k )) £ 1!, |i > 0 ,
and go to Step 4.
Step 4. Set x k+1 = x k + p,(x k )h(x k ), set k = k + 1 and return to Step 2.
The performance of the algorithm is summarized below. Theorem 1: Suppose that the set
n(z°) = {x\x e n, /oO) > /o(x 0 )}
is compact, and has a non-empty interior, which is dense in tt(x°). Let x* be any limit point of the sequence x°,x l ,... ,x k ,..., generated by the algorithm. Then the Kuhn-Tucker conditions are satisfied at x*.
For a proof of this result and for more efficient algorithms the reader is referred to (Polak [1971]). Remark: If ho(x k ) < 0 in Step 2, then the direction h{x k ) satisfies fo x {x k )h(x k ) > 0, and fi(x k ) + f ix (x K )h(x k ) < 0, 1 < i < m. For this reason h(x k ) is called a (desirable) feasible direction. (See Figure 5.8.)
5.5. APPENDIX 73
5.5 Appendix
The proofs of Lemmas 4,7 of Section 2 are based on the following extremely important theorem (see Rockafeller [1970]).
Separation theorem for convex sets. Let F, G be convex subsets of R n such that the relative interiors of F, G are disjoint. Then there exists A G R n , A / 0, and 9 G R such that
A's < 9 for all geG A'/ > 9 for all / G F .
Proof of Lemma 4: Since M is stable at 6 there exists if such that
Af (6) - Af (S) < K\b - b\ for all b G 5 . (5.47)
In i? 1+m consider the sets
F = {(r, 6)|6 e R m , r> K\b-b\} , G = {(r, b)\b G F, r < M{b) - M(S)} .
It is easy to check that F, G are convex, and (5.47) implies that F n G = <p. Hence, there exist (Aq, • • •, A m ) / 0, and 6 such that
A 0 r + J2 x ibi < 0 for (r, 6) G G ,
i=l m
X 0 r + ^ XA > 6 for (r, b) G F .
(5.48)
i=l
From the definition of F, and the fact that (Ao, ■ ■ ■, A m ) / 0, it can be verified that (5.
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